Monday, November 30, 2009

I have spotted the Biology planning experiment question 2009

After knowing what was the questions came out in Biology Paper 2. I refined my spotted questions in Paper 3 to six experiments at around 12:30pm. My first spotted experiment was Experiment 4.1 Studying the effects of temperature on the activity of salivary amylase Page 92, and it came out in the real Biology Paper3 2009! The biological detergent contain protease and amylase.

I want to praise the Lord and give all the glory to Him! Because He answered my prayer and gave me wisdom to spot the question.

Let us continue praying to our Lord Jesus to ask for wisdom for all of our coming exams!

Announcement

I have made a post on SPM tips for today Biology Paper 3. Please check out http://biology-spm-tips-and-helps.blogspot.com/

Good luck and wishing you all the best!

Friday, November 13, 2009

Tactic That You Can Use To Score Better In Chemistry (Part 4)

Hi again, I hope you are doing well with your revision. By this time, you should completed Plan B. Now let’s see what you should do in Plan C. In Plan C, you will be answering all the essay questions in Paper 2, Section B and Section C.

Since you don’t have so much time left, I suggest that you learn straight from the answer given. Below are steps that you can follow:

Step 1: Read and understand the essay question
Step 2: Underline or circle the action word/keyword in the question so that you know what to
answer
Step 3: Go through the answer given
Step 4: Underline or circle the main point/keyword in each paragraph of the answer
Step 5: Remember the main point/keyword and then understand the answer given
Step 6: Rewrite the essay based on the main point/keyword that you have memorized without
referring back to the answer
Step 7: Check the essay you wrote with the answer given
Step 8: If you get your answer correct, then repeat the steps above with a new essay question. If
your answer is wrong, rewrite the essay.

When you go through the answer given, please make sure that you understand the answer. If you not sure or feel that the answer is incorrect, you should always check back in the reference books or check with your chemistry teacher.

Lastly, Plan D is that you set a day and doing a full set of the question papers following the exact time given in answering the SPM Chemistry Exam paper.

Well, that’s all about the tactics that you can use in order to score better in SPM. I will compile some spotted questions for this coming SPM Chemistry 2009 in my coming post. Just subscribe to my blog so that you know when I update my blog.

All the best to you!

Thursday, November 5, 2009

Chemistry: Multiple Choice Problem Solving Question 3

Which of the following does not involve oxidation and reduction method?

A.Electrolysis of molten lead(II) chloride using carbon electrodes
B.Addition of zinc powder to copper(II) sulphate solution.
C.Steam is passed over hot magnesium powder.
D.Addition of silver nitrate solution to sodium chloride solution.

Explanation:

This is a double decomposition reaction. It doesn't involve changes in oxidation numbers of ions.

AgNO3 + NaCl --> AgCl + NaNO3

If you calculate the oxidation numbers of each ions, they does not change before and after the reaction.

Question asked by Ryane.

Chemistry: Multiple Choice Problem Solving Question 2

Which of the following methods is suitable for preparing lead(II) bromide?

A. Heat lead(II) sulphate and potassium bromide
B. Heat lead(II) oxide and bromine.
C.Add lead powder to aqueous sodium bromide.
D.Mix Lead(II) nitrate solution with sodium bromide solution.

Explanation:

Lead(II) bromide is the stable salt of lead and hydrobromic acid. It is typically formed by precipitation from lead(II) nitrate by the addition of a water-soluble bromide, for example sodium bromide solution. This method is called Double Decomposition Reaction.
Therefore, the answer is D.

Anyway, Lead(II) bromide is not in the SPM syllabus.



Question asked by Ryane.

Chemistry: Multiple Choice Problem Solving Question 1

2HCl + Na2CO3 --> 2NaCl + CO2 + H2O
What volume of 0.2moldm-3 solution of sodium carbonate is required to react completely with 50cm3 0.5moldm-3 hydrochloric acid?
A.31.5cm3
B.62.5cm3
C.125cm3
D.250cm3

Explanation:

No. of moles of HCl = (50x0.5)/1000
= 0.025

From the balanced equation given,
2 mol of HCl react completely with 1 mol of Na2CO3
Therefore, 0.025 mol of HCl will react completely with 0.025/2=0.0125 mol of Na2CO3

0.0125 = (0.2V)/1000
0.2V = 12.5
V = 12.5/0.2
= 62.5

Therefore, volume of sodium carbonate required is 62.5 cm3.

Question asked by Ryane.